Two Dimensional Arrays (courtesy of Dr. Huo)

The following program is the base for the game: tic-tac-toe. Don’t modify the structure of the main program. Complete three parts as required. Compile and run this program, and then you can play the game. Have fun!

#include<iostream>

using namespace std;

const int DIM=3;

int main()

{

int row, col;

int blanks=DIM*DIM;

char chessboard[DIM][DIM];

bool putchecker;

int count1=0, count2=0, count3=0, count4=0;

//initChessBoard

//set all the elements of the ChessBoard to blanks

//Complete this part

//printChessBoard

//print all the elements of the chessBoard with each row in one line

//Complete this part

char cur='O';

cout<<"Input position(row col)or(-1 -1) to exit; It is the turn of " <<cur<<endl;

cin>>row>>col;

while(row!=-1 && col!=-1)

{

//complete this part

/* if i and j are not out of bound(that is, i and j are in the range of 0 and DIM-1)

and chessboard[i][j] is not occupied(that is, the value of chessboard[i][j] is blank),

set chessboard[i][j] to be the value of cur and set putchecker to true. Otherwise, set putchecker to false.*/

if(!putchecker)

{

cout<<"Invalid move"<<endl;

}

else

{

--blanks;

// print ChessBoard

/* We declare four variables count1, count2, count3, count4

to represent the occurrence number of x in row number row, column number col,

in the main diagonal, and in the opposite diagonal. If after calculation, count1,

count2, count3 or count4 equals to DIM cur wins*/

for(int i=0; i<DIM; ++i)

{

//complete the following

// if the element in position (row, i) is cur, count1 is increased by 1.

// if the element in position (i, col) is cur, count2 is increased by 1.

/* if x is in the main diagonal, and the element in position (i, i) is cur, count3 is increased by 1.*/

/* if x is in the opposite diagonal, and the element in position (i, DIM-1-I) is cur, count4 is increased by 1.*/

}

if(count1 == 3 || count2 == 3 || count3 == 3 || count4 == 3)

{

cout<< cur << " Wins"<<endl;

return 0;

};

if(blanks==0)

{

cout<< "Ties"<<endl;

return 0;

}

if(cur=='X')

cur= 'O';

else cur='X';

}

cout<<"Input position(row col) or(-1 -1) to exit; It is the turn of" <<cur<<endl;

cin>>row>>col;

}

}